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[2020-02-06 Thu 16:31]
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Session 67: Proof of Green’s Theorem | Part C: Green’s Theorem | 3. Double Integrals and Line Integrals in the Plane | Multivariable Calculus | Mathematics | MIT OpenCourseWare

1 Chalkboard

Figure 1: Proof of Green’s Theorem

Figure 1: Proof of Green’s Theorem

Figure 2: 2 observations

Figure 2: 2 observations

Figure 3: Proof of one part

Figure 3: Proof of one part

Figure 4: Cut (R) “vertically simple”

Figure 4: Cut (R) “vertically simple”

Figure 5: Main step of prove

Figure 5: Main step of prove

Figure 6: Line integrals

Figure 6: Line integrals

Figure 7: Sum of all line integrals

Figure 7: Sum of all line integrals

Figure 8: Doble integral of internal region

Figure 8: Doble integral of internal region

2 Which step we need to do for proofing Green’s Theorem?

2.1 Front

Which step we need to do for proofing Green’s Theorem?

Only describe the steps

2.2 Back

Green’s Theorem: \({\displaystyle \oint_C M \dd{x} + N \dd{y} = \iint_R (N_x - M_y) \dd{A}}\)

  1. First Observation

    • Separate this integral as \(N = 0\) and \(M = 0\)
      • \({\displaystyle \oint_C M \dd{x} = \iint_R - M_y \dd{A}}\)
      • \({\displaystyle \oint_C N \dd{y} = \iint_R N_x \dd{A}}\)
    • The sum of both equation is the complete proof of Green Theorem
  2. Second Observation

    • Decompose \(R\) into simpler regions, creating new paths around this new regions. The sums of the regions is \(R\) and the sum of \(C_i\) path around each region is \(C\) (this is true, because all path are counterclockwise, and 2 path in the boundaries with opposite orientations is \(0\)).
    • You can use “vertically simple”, “horizontal simple” or rectangles
  3. Main Step (using the separated integral)

    • Calculate the right hand side of Green’s Theorem
      • Set the outer integral
    • Calculate the left hand side of Green’s T
      • Along some size the integral is \(0\)
    • \({\displaystyle \int_a^b M(x,c) - M(x,d) \dd{x}}\)

Any region can be approximated as closely as we want by a sum of rectangles, Green’s Theorem must hold on arbitrary regions