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[2020-02-05 Wed 21:20]
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Session 12: Equations of Planes II | Part B: Matrices and Systems of Equations | 1. Vectors and Matrices | Multivariable Calculus | Mathematics | MIT OpenCourseWare

1 Chalkboard

Figure 1: Equations of Planes

Figure 1: Equations of Planes

Figure 2: Point in the plane

Figure 2: Point in the plane

Figure 3: Normal vector and vectors on the plane

Figure 3: Normal vector and vectors on the plane

Figure 4: Extract normal vector from plane equation

Figure 4: Extract normal vector from plane equation

Figure 5: Check vector parallel or perpendicular to a plane

Figure 5: Check vector parallel or perpendicular to a plane

2 What do we need to determinate a plane?

2.1 Front

What do we need to determinate a plane?

2.2 Back

  • Point \(P_0 = (x_0, y_0, z_0)\)
  • Normal vector: \(\vb{N} = \ev{a,b,c}\)
    • Orthogonal to the plane
  • Let \(P = (x, y , z)\) arbitrary point in the plane
  • \(\vec{P_0P}\) is orthogonal to \(\vb{N}\)
    • \(\vb{N} \vec{P_0P} = 0\)
    • \(\Leftrightarrow \ev{a,b,c} \cdot \ev{x - x_0, y - y_0, z-z_0} = 0\)
    • \(\Leftrightarrow a(x - x_0) + b(y - y_0) + c(z - z_0)\)
    • Quick version: \(ax + by + cz = ax_0 + by_0 cz_0\)

Also, you can determinate through 3 points in the plane, getting the normal through cross product between 2 vectors in the plane

With a point and 2 parallel vectors

3 How can we find an equation of a plane knowing all intercepts with the axis?

3.1 Front

How can we find an equation of a plane knowing all intercepts with the axis?

  • Intercepts: \((a, 0 , 0)\), \((0, b, 0)\), \((0, 0, c)\)

3.2 Back

  • Plane is \({\displaystyle \frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1}\)

4 How can we find lines in the plane?

4.1 Front

How can we find lines in the plane?

  • Describe 2 ways of write the equation of a line in the \(xy\text{-plane}\)

4.2 Back

  • Slope-intercept form
    • \(y = mx + b\)
  • Point-normal form
    • \(P_0 = (x_0, y_0)\)
    • \(\vb{N} = \ev{a, b}\)
    • \(a(x - x_0) + b(y - y_0) = 0\)

5 Can we extract the normal vector from the equation of a plane?

5.1 Front

Can we extract the normal vector from the equation of a plane?

\(x + 2y + 3z = -2\)

5.2 Back

\(\vb{N} = \ev{1, 2 ,3}\)

6 What is the equation of a plane from normal vector and 1 point?

6.1 Front

What is the equation of a plane from normal vector and 1 point?

  • \(\vb{N} = \ev{a, b, c}\)
  • \(P_0 = (x_0, y_0, z_0)\)

6.2 Back

\(ax + by + cz = ax_0 + by_0 + cz_0\)

7 How can we calculate the distance to a plane from 1 point?

7.1 Front

How can we calculate the distance to a plane from 1 point?

  • A point \(P\)
  • Equation of a plane

7.2 Back

  • A point \(P\)
  • A plane with normal \(\vb{N}\) and containing a point \(Q\)
  • Get any vector to the point \(P\) to point \(Q\) in the plane, doesn’t matter where this point is
  • Get component of \(\vec{PQ}\) in direction of normal \(\vb{N}\) to the plane
  • \({\displaystyle d = \abs{\vec{PQ}} \cos(\theta) = \abs{\vec{PQ} \cdot \frac{\vb{N}}{\abs{N}}}}\)

8 How can we calculate the distance: point to line?

8.1 Front

How can we calculate the distance: point to line?

  • Point \(P\)
  • Line with direction \(\vb{v}\)

8.2 Back

  • Point \(P\)
  • A line with direction \(\vb{v}\) and containing a point \(Q\)
  • \({\displaystyle d = \abs{\vb{QP}} \sin \theta = \abs{\vb{QP}} \abs{\frac{\vb{v}}{\abs{v}}} \sin \theta = \abs{\vec{QP} \cross \frac{\vb{v}}{\abs{v}}}}\)

You can calculate the distance with the normal

  • \({\displaystyle d = \abs{\vec{PQ} \cdot \frac{\vb{N}}{\abs{\vb{N}}}}}\)

9 How can we calculate the distance between 2 parallel planes?

9.1 Front

How can we calculate the distance between 2 parallel planes?

9.2 Back

  • Reduce it to the distance from a point to a plane
  • Get a normal vector to each plane, and check that they’re parallel each other
  • Take any point from 1st plane
  • Take any point the other plane
  • \({\displaystyle d = \abs{\vec{QP} \cdot \frac{\vb{N}}{\abs{N}}}}\)